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Mathematics 9 Online
OpenStudy (shamil98):

How to find the relative maximum value of a function? g(x) = 7/(x^2+5)

OpenStudy (shamil98):

I find the first derivative and set it to equal zero right?

OpenStudy (anonymous):

This one doesn't need calculus, it's a quadratic equation.

OpenStudy (anonymous):

I mean inverted quadratic function

OpenStudy (anonymous):

The max of the function is the min of its denominator, which will be at the vertex.

OpenStudy (anonymous):

It's already in vertex form, too.

OpenStudy (shamil98):

So, i just graph it then?....and look at the vertex?

OpenStudy (ranga):

The minimum value x^2 can take is 0.

OpenStudy (anonymous):

It's in vertex form. \[ y=(x-h)^2+k \]In this case \((h,k)=(0,5)\)

OpenStudy (shamil98):

Oh. Thanks.

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