Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

DESPERATE FOR HELP!!! Please help - I will award medals. An archer releases an arrow from a shoulder height of 1.39m. When the arrow hits the target 18m away, it hits point A. When the target is removed, the arrow lands 45m away. The distance from the top edge of the archery target to the ground is 1.5m. Find the maximum height of the arrow along its parabolic path. Point A is 24cm down from top of target. *** I can't figure out which is a, b, and c.

OpenStudy (anonymous):

it's a derivative problem.find local extrema

OpenStudy (anonymous):

I don't know what the points are to put in to solve

OpenStudy (anonymous):

u don't need points, find the function, then take the derivative of it

OpenStudy (anonymous):

y = f(x) = ax² + bx + c and the max height will be x = -b/(2a) I'm stuck after that

OpenStudy (anonymous):

a, b, and c are given, u should only have x as a variable

OpenStudy (anonymous):

yes but I cannot figure out a,b,c to use quad equation

OpenStudy (anonymous):

I tried it as linear regression but that didn't work out either

OpenStudy (anonymous):

try drawing a triangle and labeling the sides

OpenStudy (anonymous):

don't I need points like (2,10), (4,12) for example to come up with a,b,c?

OpenStudy (anonymous):

lol...

OpenStudy (anonymous):

I'm sorry - don't mean to be stupid but I am just not getting this at all

OpenStudy (anonymous):

those values in the problem are given for a reason

OpenStudy (anonymous):

yea it's ok

OpenStudy (anonymous):

i didnt mean lol in the mocking way...

OpenStudy (anonymous):

would it be (18,1.39) , (45,1.5), (0,0)?

OpenStudy (anonymous):

yes u can try that

OpenStudy (anonymous):

I did but it doesn't work. What is a,b,c? Then I can plug into equation.

OpenStudy (ranga):

Yes it is -b/2a that you have to find. But the original equation is y = f(x) = ax² + bx + c You are given 3 points on the curve and you have 3 unknowns a, b and c and so you can solve for them. x = 0, y = 1.39 x = 45, y = 0 x = 18, y = (1.5 - .24) Substitute and solve for a and b. Eliminate c as you don't need it to find -b/2a

OpenStudy (anonymous):

why did you put y=(1.5-.24) on the last equation?

OpenStudy (anonymous):

ok - when I put those in I get a=-0.0008765 b=0.0085556 c=1.39 when I solve y=-0.00087654321x^2+0.008555556+1.39 even if I solve for x that isn't giving me the height. What am I doing wrong?

OpenStudy (anonymous):

duh - I didn't do the second step for -b/2a. ok. when I do that I get -4.88

OpenStudy (ranga):

Assuming your a, b and c are correct you just plug in to the equation you had for maximum height -b/2a

OpenStudy (anonymous):

can a height be a negative?

OpenStudy (ranga):

It depends on how the parabola is oriented. But for this problem I would expect a positive height. -b/2a. Your b is positive and a is negative so -b/2a should be positive.

OpenStudy (anonymous):

I put in -0.0085556/2(-0.0008765) => -0.008556/-0.001753=-4.88

OpenStudy (ranga):

a negative divided by a negative is positive.

OpenStudy (anonymous):

I have spent over 2 hours on this question and am brain dead. The calculator also gave me a negative number

OpenStudy (ranga):

Do you know if the answer is 4.88 meters?

OpenStudy (anonymous):

not for sure. That's what I came up with.

OpenStudy (ranga):

Is this problem from a textbook or online? Will you only know if it is right or wrong after submitting the answer and wait for the teacher to tell you?

OpenStudy (anonymous):

It's a homework question. No, I won't be submitting it online. I have to write it out and turn in

OpenStudy (ranga):

The 4.88 is correct if your a, b and c are correct. One way to check if its is correct is to put back the x values of the three points on the curve and see if it matches the y values. I already know your c is correct because when x = 0, y = c = 1.39

OpenStudy (anonymous):

Can I ask for help for 1 other question? I did it as a linear regression but I know it isn't right. Well - my answer for linear regression is right but I don't think that's how I'm supposed to answer it. The question is: The table shows how the weight and height of an arrow affects it. Graph the data in the table to find a linear and a quadratic model for the data. Which model is a better fit. The chart is: 140 150 170 175 205 on top and underneath is 1.4 1.25 0.93 0.78 0.43

OpenStudy (ranga):

Did you use a standard formula for linear regression and if so do you have a formula for quadratic model?

OpenStudy (anonymous):

no. I put it into the calculator without understanding what I was doing and the calculator gave me the linear regression

OpenStudy (anonymous):

It gave me : mean x=168 mean y=0.958 intercept(a)3.51 slope(b) -0.12 and y=3.51-0.015x

OpenStudy (ranga):

If you are allowed to use calculators then there are good linear regression calculators and quadratic regression calculators online where you just put in the x,y values from the table and the calculator will give you the regression equation. Here is one quadratic regression calculator: http://www.had2know.com/academics/quadratic-regression-calculator.html

OpenStudy (anonymous):

y = -0.0018x^2 - 0.2696x + 123.108 is what that gave me from that calculator

OpenStudy (ranga):

Here is a linear regression calculator: http://ncalculators.com/statistics/linear-regression-calculator.htm

OpenStudy (anonymous):

Regression Equation Y=3.5125 + -0.0152 x

OpenStudy (anonymous):

do I graph both to see which is a straighter line?

OpenStudy (ranga):

So the equations for the linear and quadratic regressions will be the answer to the question: find a linear and a quadratic model for the data. To find out which is a better fit, I think you will need to find something called a correlation coefficient r. Whichever one gives an r closer to 1 is the better model. My statistics is a bit rusty though. Haven't used it in a long time.

OpenStudy (ranga):

If you graph those two regression lines, the linear one will be a straight line and the quadratic one will be a curve (a parabola).

OpenStudy (anonymous):

I haven't taken statistics yet - only the portion we did in geometry last year and I don't remember a correlation coefficient. I will have to go back to my notes. Thank you so much for your time and knowledge. I was ready to through my book I was getting so upset at not understanding what I was doing. I'm glad they let us use calculators but sometimes I think I don't learn it as well because I'm not always sure where I'm pulling the numbers from to plug in.

OpenStudy (ranga):

You are welcome. In the first problem, put back those three data points to make sure the a, b, c that you solved are correct. If they are then 4.88 meters is the correct answer.

OpenStudy (anonymous):

Thank you. I will do that now.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!