Question

State the x-coordinate of the x-intercept in quadrant II for the function below.
f(x)=4x^3-12x^2-x+15

Answer 1

how can an \(x\) intercept be in a quadrant? an \(x\) intercept is on the \(x\) axis

Answer 2

my some miracle this factors as
\[(2 x-3) (2 x-5) (x+1)\] so the zeros are easy enough to find
what quadrant they are in is anyone's guess

Answer 3

*by

Answer 4

I like totally agree with Mr. Satellite73 in saying that x-intercepts do no lay in any quadrant because they lay on the x-axis.
Points in the form (positive number, positive number) are in the first quadrant.
Points in the form (negative number, positive number) are in the second quadrant.
Points in the form (negative number, negative number) are in the third quadrant.
Points in the form (positive number, negative number) are in the fourth quadrant.
x-intercepts have the y=0 and there is no way 0 could ever be positive or negative like ever.