Question

\[\sqrt{{{a}^{2}}-{{x}^{2}}}\text{ Help me solve this thing please.}\]

Answer 1

ops, its supposed to be an integral.

Answer 2

\[\int{{}}(\sqrt{{{a}^{2}}-{{x}^{2}})}\]
there

Answer 3

so here we have a function inside of a function like this: f(g(x))
after changing the radical into an exponent, you will want to use the chain rule ^_^

Answer 4

I am afraid I am too inexperienced to follow through your logic :S

Answer 5

no problem!
can yo do the first step, change the radical into an exponent?

Answer 6

\[\int{(}{{A}^{2}}-{{x}^{2}}{{)}^{(1/2)}}\]

Answer 7

ok ??

Answer 8

let x = asin u \(\rightarrow dx = acos u du\)
x^2 = a^2 sin^2 u
a^2 - x^2 = a^2 - a^2sin^2 u
get this part?

Answer 9

no??

Answer 10

still have some steps to get the answer, but if you don't get this part I am better stop here. Good luck

Answer 11

can you help me with this part here ? a^2 - x^2 = a^2 - a^2sin^2 u

Answer 12

nvm I got everything up until now @Loser66

Answer 13

\[\int{{}}\sqrt{({{a}^{2}}-{{a}^{2}}si{{n}^{2}}theta)}\]

Answer 14

so?

Answer 15

you miss cos \(\theta\)d\(\theta\)

Answer 16

I use u and you use \(\theta\), hopefully you can see they are just notation.

Answer 17

and then ?