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compute the integrals ∫3 ( ln(2x)/x ) dx
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let u = ln 2x
yes how to solve it then i did not know :(
is du= -2 dx
\[\int\limits \frac{ 3\ln 2x }{ x }dx\Rightarrow \frac{ 3 }{ 2 }\int\limits u du\]
du = 2/x dx
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so it will be 3/2 ∫ ln 2x . 2/x dx ???
\[\int\limits \frac{ 3\ln 2x }{ x }dx= \frac{ 3 }{ 2}\int\limits \ln 2x\cdot \frac{ 2 }{ x }dx=\frac{ 3 }{ 2}\int\limits u \,du\]
\[=\frac{ 3 }{ 4 }\left( \ln 2x \right)^2 + C\]
thank you (L)
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