Question

how do I do these??? please dont give answer - Do I have to factor it out?
\
State the vertex of the following function:
f (x ) = (x - 6)^2+ 8 .

Answer 1

The vertex is a maximum or minimum value of the parabola.

In this case, f (x ) = (x - 6)^2+ 8, for the x-coordinate of the vertex, you want to find the value of x that makes (x - 6)^2+ 8 as small as possible.

Answer 2

-8 and 6?

Answer 3

notice that your equation is already in vertex form http://www.mathwarehouse.com/geometry/parabola/images/standard-vertex-forms.png

so your vertex is at \(\large f (x ) = (x -\color{red}{ 6})^2+ \color{red}{8} \)

Answer 4

\(\large \begin{array}{llll}
&x&y\\
f (x ) = (x - &6)^2+ &8
\end{array}\)

Answer 5

@mocham >>>-8 and 6?

No.

The x value of 6 does minimize the function.

So, you have (6,?) as the vertex of the parabola.

Now, evaluate (x - 6)^2+ 8 for x = 6 to get the y-coordinate of the vertex.

Answer 6

6 and 8?

Answer 7

Yes, write those as coordinates.

(6,8)

Answer 8

(6,8) my vertex =)

Answer 9

Correct.

Answer 10

thank you!

Answer 11

You are welcome.