Evan is making a table that will be created in the shape of the figure below. The table top is a triangle attached to a rectangle. To purchase the right amount of paint, he needs to know the area of the table top. He can only spend $10 on paint, which is enough to cover 150 ft2 of surface area. What is the maximum length of the base of the rectangle he can build?
First find the area of the triangle, which is half base times height... so the triangle area = 0.5 * 4 * 6 = 12
So he uses up 12ft^2 of paint on the triangle, and had 150ft^2 total paint... so now has 150-12 = 138 ft^2 |dw:1382747974249:dw| k so the area of the rectangle can be 138. Area is length*width, so 6*x = 138 Now just divide both sides by 6.
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which part confused you?
all
lml
haha okay lets start from the triangle, it's got a base of 4ft and a height of 6ft, so use area=0.5*base*height A=0.5*4*6 = 12 ft^2
mhm
and he has 150ft^2 of paint total. The triangle takes 12ft^2, so that leaves 150-12 = 138 ft^2 for the rectangle, right?
The total surface area has to add up to 150 ft^2, of the rectangle, and the triangle. The triangle is 12 ft^2, which leaves 138 ft^2 for the rectangle, so they add up to 150 ft^2... make sense?
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