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Mathematics 14 Online
OpenStudy (anonymous):

Evan is making a table that will be created in the shape of the figure below. The table top is a triangle attached to a rectangle. To purchase the right amount of paint, he needs to know the area of the table top. He can only spend $10 on paint, which is enough to cover 150 ft2 of surface area. What is the maximum length of the base of the rectangle he can build?

OpenStudy (anonymous):

OpenStudy (agent0smith):

First find the area of the triangle, which is half base times height... so the triangle area = 0.5 * 4 * 6 = 12

OpenStudy (agent0smith):

So he uses up 12ft^2 of paint on the triangle, and had 150ft^2 total paint... so now has 150-12 = 138 ft^2 |dw:1382747974249:dw| k so the area of the rectangle can be 138. Area is length*width, so 6*x = 138 Now just divide both sides by 6.

OpenStudy (anonymous):

?

OpenStudy (agent0smith):

which part confused you?

OpenStudy (anonymous):

all

OpenStudy (anonymous):

lml

OpenStudy (agent0smith):

haha okay lets start from the triangle, it's got a base of 4ft and a height of 6ft, so use area=0.5*base*height A=0.5*4*6 = 12 ft^2

OpenStudy (anonymous):

mhm

OpenStudy (agent0smith):

and he has 150ft^2 of paint total. The triangle takes 12ft^2, so that leaves 150-12 = 138 ft^2 for the rectangle, right?

OpenStudy (agent0smith):

The total surface area has to add up to 150 ft^2, of the rectangle, and the triangle. The triangle is 12 ft^2, which leaves 138 ft^2 for the rectangle, so they add up to 150 ft^2... make sense?

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