Help me Please!!!
@ranga
I need help with three more questions do you think you can help me with them??
Post them here one at a time and I will try.
Are you going to post now?
Triangle DOG was rotated to create triangle D'O'G''. Describe the transformation using details and degrees. Imagine points D and D' were two points on a circle named O that had the origin as its center. Now imagine points O and O' were to also lie on a circle named T with the origin as its center. What type of circles would O and T create?
sorry I was eating
the second question The figure below shows two congruent triangular parks. What equation would help you to solve for the side length of BC and EF? Explain your reasoning using complete sentences.
this is the first question pic
In the first picture, what they have ended up doing is reflections on both the x axis and the y axis. (x,y) has become (-x, -y) for all three points.
Reflection and both x and y axes together is also called the reflection about the origin.
Yeah that was the question i got wrong because my dumb substitute so she making me do the whole assignment again --____--
They say "Describe the transformation using details and degrees" To get to D' from D, the point D is rotated 180 degrees with the origin as the center. To get to O' from O, the point O is rotated 180 degrees with the origin as the center. "What type of circles would O and T create?" The two circles will be concentric (meaning same centers) and the origin will be the center.
Ohh ok well good that i got the 180 degrees right
For the second problem, the two triangles are congruent which means they have the exact same three lengths for the sides. And therefore .... can you tell me what the equation should be?
2x-3=x+5
They tell you the triangles are congruent that means they have the exactly same three sides. Looking at the diagram we can see: AC = FD = 9 AB = ED = 17 Therefore, CB and EF must be the same. CB = 2x - 3 and EF = x + 5 So the equation is: 2x - 3 = x + 5
Yes. You got it right.
Yay! cause i was scared that i was getting it wrong
Good. You got all your questions answered?
theres one more and then im done for geometry.
last question Determine if the two figures are congruent and explain your answer. If they are congruent, tell which rigid motions were used.
That one i was very confused
Square of the distance between two points = square of x difference + square of y difference. Compare the lengths of CB and GF. Are they equal?
Yes they are equal
Compare CD and GH; AD and EH; AB and EF
yeah the all have equal sides but just position differently
That means the two figures are congruent. You may have to explain in detail why you think the two sides such as CD and GH are equal. It could be something like: to go from C to D I have to take two units to the left along the x axis and 4 units down along the y axis. so the distance CD = sqrt(2^2 + 4^2) You can do the same with GH and say GH = sqrt(4^2 + 2^2) and so CD = GH
Thank you so much for helping me :)
Whats ''sqrt" ??
square root
ohh and what about ''^''?
exponent.
ohh ok well again thank you
This is what I meant: \[\Large CD = \sqrt{2^{2} + 4^{2}}\]
ohh ok that makes alot of scene
Distance between two points: \[\Large (x _{1}, y _{1})\] and \[\Large (x _{2}, y _{2})\] Distance formula:\[\Large d = \sqrt{(x _{2} - x _{1})^{2} + (y _{2} - y _{1})^{2}}\]
That is the formula we used to calculate the length of CD. Square the difference in x coordinates and add it to the square of the differences in y coordinates and take the square root.
There is one more part to this question: "tell which rigid motions were used" So you have to describe how to move the first figure to get to the second figure.
I think its a refflection
Just one simple reflection won't make the first figure look like the second. There is a little bit of turning and sliding involved.
There are so many ways to do it that there may not be just one answer.
well its fine thanks again
Okay. This is how I will move the object: Slide the top object down by 1 unit until D and H are the same point. Then rotate the figure clockwise until C and G align. Then flip it over 180 degrees. Ok. You are welcome.
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