Integration! \[\int \frac{x+5}{2x + 3} dx\]
again, I suggest: long division first
Break it in half or not? \[\int \frac{x}{2x + 3} + \frac{5}{2x + 3} dx\]
why? you are always go on that way?
whenever you see the degree of numerator > or equal the degree of denominator, the first thing you should do is take long division.
hey!! or you don't know how to do it? aha!! if so, you just ask.
Sorry, I got pinged by another question. I'm still here. :)
Anyway, yeah, I tend to go for the breaking or the easy substitutions because I'm not good at polynomial division.
so, just practice, it's not hard. go ahead, show me your long division. I can check or correct if you have a mistake
Ok... so I need to make a "fake" 2x + 3 in the numerator, right? By writing something like \(\frac{1}{2}(2x + 3) - 1.5 + 5 \)
I take it the thing I was doing was... some other thing entirely?
I am sorry, let me explain
Thank you. :)
Oh, that is really nice! Medal for you! Two if I could!
It's actually similar to what I was doing then. Just totally different thought process to get there. Thank you!
\[\int \frac{1}{2} - \frac{7}{4x + 6} dx\]\[\frac{x}{2} - 7 \int \frac{1}{4x + 6} dx\] \(u = 4x + 6\) \(du = 4 dx\) \[\frac{x}{2} - \frac{7}{4}\ln |4x+6| + C \]
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