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Mathematics 13 Online
OpenStudy (anonymous):

Integration! \[\int \frac{x+5}{2x + 3} dx\]

OpenStudy (loser66):

again, I suggest: long division first

OpenStudy (anonymous):

Break it in half or not? \[\int \frac{x}{2x + 3} + \frac{5}{2x + 3} dx\]

OpenStudy (loser66):

why? you are always go on that way?

OpenStudy (loser66):

whenever you see the degree of numerator > or equal the degree of denominator, the first thing you should do is take long division.

OpenStudy (loser66):

hey!! or you don't know how to do it? aha!! if so, you just ask.

OpenStudy (anonymous):

Sorry, I got pinged by another question. I'm still here. :)

OpenStudy (anonymous):

Anyway, yeah, I tend to go for the breaking or the easy substitutions because I'm not good at polynomial division.

OpenStudy (loser66):

so, just practice, it's not hard. go ahead, show me your long division. I can check or correct if you have a mistake

OpenStudy (anonymous):

Ok... so I need to make a "fake" 2x + 3 in the numerator, right? By writing something like \(\frac{1}{2}(2x + 3) - 1.5 + 5 \)

OpenStudy (anonymous):

I take it the thing I was doing was... some other thing entirely?

OpenStudy (loser66):

I am sorry, let me explain

OpenStudy (anonymous):

Thank you. :)

OpenStudy (loser66):

OpenStudy (anonymous):

Oh, that is really nice! Medal for you! Two if I could!

OpenStudy (anonymous):

It's actually similar to what I was doing then. Just totally different thought process to get there. Thank you!

OpenStudy (anonymous):

\[\int \frac{1}{2} - \frac{7}{4x + 6} dx\]\[\frac{x}{2} - 7 \int \frac{1}{4x + 6} dx\] \(u = 4x + 6\) \(du = 4 dx\) \[\frac{x}{2} - \frac{7}{4}\ln |4x+6| + C \]

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