Question

A 19 ft ladder leans against a wall. The bottom of the ladder is 4 ft from the wall at time t=0 and slides away from the wall at a rate of 2ft/sec.

Find the velocity of the top of the ladder at time t=2.

The velocity of ladder at time t=2 is
I hate word problems

Answer 1

find y and tell me which formula you used using the variable x, y and L[for hypotenuse] ^_^

Answer 2

lmk if i should just solve without interaction lol

Answer 3

lol sorry I was getting a drink

Answer 4

y=18.5, and formula would be umm im not 100% sure

Answer 5

yes that is right. and you (must have) used the Pythagorean Theorem:
\[L^2 = x^2 + y^2\]

Answer 6

i actually read the problem too fast. that is what y is at t = 0.
however, we are studying the problem at t = 2.

therefore x is not 4 since it slid at 2ft/s for 2 s

and y has to be found again using that formula

Answer 7

do you know how to find x after 2 seconds?

Answer 8

oh lol so now its is y=18.89

Answer 9

not quite. do the math again for x = 4 + 2*(dx/dt)

Answer 10

Hmm 18.02? wait are we still doing a^2+b^2=c^2?

Answer 11

yes.

but x at t = 0 is 4 ft

it slides at 2 ft/s for 2 seconds

making x at t = 2 --> 4ft + 2s*2ft/s = 8 ft

Answer 12

ahh tricky so y=17.23?

Answer 13

yes