Question

I have molarity (6.70M), I need to figure out % concentration, with a molar mass of 60.05g/mol. Or just give me the equation I need so that I know how to solve similar problems in the future, thank you.

Answer 1

percent concentration by mass?

6.70 M = 6.7 moles/L

you have 6.7 moles in 1 L,

mass= moles*molar mass = 6.7mole.*60.05g/mol=402.335 g of solute

you would also need to know the density of the solution or the density of the solute.

Answer 2

It's a vinegar solution, so 1g/mL (is the value given). The only problem with that, I multiply everything out 6.70 Mol/ 1 Litre x 60.05 g / 1 mol x 1 g / 1 mL but I come out with a percent that seems very wrong, since the concentration of acetic acid is supposed to be no more than 5%. I was hoping that I was misunderstanding something, or just didn't know the proper equation or something. The only other possibilities available ar that somehow the measurements in all of our tests are somehow off, but off by the same amount, or that the concentration of the acetic acid is higher than one would expect.

Answer 3

If the molarity is 6.70M, then you have 402.335 g of solute per liter, and a liter is 1000 g. Thus you have you have a 40.234 % by mass solution

Answer 4

If it's supposed to be around 5%, then your molarity is very off.