Question

At time t seconds, a particles distance s(t), in micrometers (um), from a point is given by s(t) = e^t - 1. WHat is the average velocity of the particle from t=2 to t=4?

Answer 1

The average velocity is given by the expression \[\frac{s(4) - s(2)}{4-2}\]

Answer 2

Evaluate s(4) and s(2) and solve

Answer 3

Thank you mebs. would the answer be around 23? and do I use um/s?

Answer 4

@mebs

Answer 5

\[\frac{ (e^{4} -1) - (e^{2}-1) }{ 2 }\]

Answer 6

\[\frac{ e^{4} -1 -e^{2} +1 }{ 2 }\]

Answer 7

\[\frac{ e^{4} - e^{2} }{ 2 }\]

Answer 8

= 23.6 um/s

Answer 9

=24 um/s

Answer 10

Correct well done

Answer 11

thank you thats what I got as well. But, why did you do this e4−1−e2+1?

Answer 12

I simplified it .

Answer 13

shouldn't it still be e^4-1 - e^2 -1?

Answer 14

oh nvm i see

Answer 15

thank you

Answer 16

you have to distribute the - sign to al.

Answer 17

yw =))