Trigonometric substitution, Can you please help me out with the first one ? Just so that I can understand what to do.\ https://www.dropbox.com/s/qr65brhchm446fd/Screenshot%202013-10-26%2020.26.13.jpg
they completed the square, which would be necessary when solving these to put them in the proper form. of a^2 ± x^2 but for the first one u = x-1
"completed the square" what do you mean by that ?
The thing where you rewrite a quadratic like \(ax^2 + bx + c\) in the form \(a(x + b)^2 + c\)
Er, the b and the c aren't the same in those. But do you recognize it now.
\[\int{\frac{1}{\sqrt{x(x-2)+10}}}\]
The thing where you rewrite a quadratic like \(ax^2 + bx + c\) in the form \(a(x + d)^2 + e\) There. :D
\[\int{\frac{1}{\sqrt{x(x-2)+10}}}\] is that it ?
making a perfect square is quite a easy task.... just divide num. of x, add and subtract its square then.... then (x+ (coeff of x)with sign /2)^2 remaining is just addition and subtraction
so am I doing it right or what
wrong...
in first eqn coeff of x is -2, -2/2 = -1 (x^2-2x +1^2) -1^2 +10
are u okay wid it?
eqn coeff?
When rephrased coherently I think it says "In the first equation, the coefficient of x is -2, -2/2 = -1." And then he explains how to complete the square. :D
my mistake... forgot to add comma :P
in first eqn,
ok what about that part ? -2/2 = -1
coeff of x/2
is there any x/2 in the exercise?
do you know the meaning of coefficient?
like if 2x coefficient of x is 2
yep..
?\
What part are you getting stuck on Christos? :O The completing the square stuff?
i said yes... :D u did that gud
yes @ZeHanz thats where I stuck
It looks like they did the `completing the square` for you, and they're asking you what substitution you should make. In part a) \(\Large u\quad=\quad 3\tan\theta\)
But as Euler stated, maybe they want to know how you got from x to u. I'm a little confused on the wording of the question :(
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