Question

Solving quadratic inequalities
22x2 + 16x = 64 < 0

Answer 1

I think your question should be like 22x2 + 16x - 64 < 0. Am I right?
@pastorshall

Answer 2

yes

Answer 3

@pastorshall OK so wait

Answer 4

+64 +64?

Answer 5

haven't done these in a while I forgot

Answer 6

\[22x^2 + 16x - 64 < 0 \]
\[11x^2 + 8x -32 < 0 \](Dividing both sides by 2)
comparing it with \[ax^2 + bx +c < 0\] we find
a= 11, b= 8, c=-32
Now let us use quadratic formula to solve this quadratic inequality.
\[ \frac{-b \pm \sqrt{b^2-4ac}}{2a}<0\]
\[ \frac{-8 \pm \sqrt{8^2-4 \times 11 \times (-32)}}{2 \times 11}<0\]
\[ \frac{-8 \pm \sqrt{64+1408}}{22}<0\]
\[ \frac{-8 \pm \sqrt{1472}}{22}<0\]
Now you can solve onward it

Answer 7

I am looking back at the problem and it shows that it is
22x2 + 16x +64 < 0
But that just can't be right, could it??

Answer 8

not - 64

Answer 9

I wonder if that is a typo?