write a polynomial function in standard form with the given zeros. x=3,0
y = (x-a)(x-b) is a polynomal with zeros x=a,b
helps ?
the idea been x = 3 => x-3 = 0 => (x-3) = 0 x =0 => x - 0 = => (x-0) = 0 thus now, but using the "zeros" or "solutions" of the quadratic equation, that is the "x-intercepts" we know its roots, that is (x -3) and (x-0) so just multiply those to get your original polynomial
multiply wat
\(\bf x = 3 \implies x-3 = 0 \implies \color{red}{(x-3)} = 0\\ \quad \\ x =0 \implies x - 0 =0 \implies \color{red}{(x-0)} = 0\\ \quad \\ \color{red}{(x-3)(x-0)} = 0\implies \square x^2+\square x+\square = 0\)
i dont know how to get the answer tho
just multiply the binomials, the exercise assume you do know polynomials multiplication
thank u
yw
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