would the answer be 64 ft?
H (t ) = -16t + 64t
14.Find the maximum height of the ball. (Hint: this is the maximum function value)

Question

would the answer be 64 ft?
H (t ) = -16t + 64t
14.Find the maximum height of the ball. (Hint: this is the maximum function value)

campbell_st · Answer

well is the equation 

$$H(t) = -16t^2 + 64t$$

anonymous · Answer

probably + 14

you need to complete the square to have your parabola in the form:

$$y = a(x-h)^2 + k$$

the point (x, y) = (h, k) is the vertex.

if a < 0 [our case] (h, k) is the highest point
if a > 0 (h, k) is the lowest point

campbell_st · Answer

if so... the max height is on the line of symmetry of the equation 

$$t = -\frac{b}{2a}$$

you have a = -16 and b = 64

find t and substitute to find max height

jdoe0001 · Answer

the maximum  height will be found at the vertex of the parabola equation, and for an equation like so $\bf ax^2+bx+c$  you can get the vertex coordinates at $\bf \left(-\cfrac{b}{2a}\quad ,\quad  c-\cfrac{b^2}{4a}\right)$

campbell_st · Answer

or you can find the 1st derivative and the solve that... for t. 

then substitute to solution into the original equation...

ranga · Answer

The answer you got is correct.

anonymous · Answer

oh go0d! thank you