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Please Help!!! D: Evaluate the Integral of (4u^2- 5u^-1)du
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use the standard integrals integral of a x^n = a x^(n + 1) / (n + 1) integral of x^-1 = ln x
how would I write that out?
in the case of 4 u^2 its [4 u^(2 + 1) ] / (2 + 1) simplify that
so that would simplify to 4u^3/3... right?
right
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now do the same to 5u^-1 which would simplify to 5?
no - check my first pos
the formula does not work for u^(-1)
so 5 ln |u| ?
yes
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+c ?
yes + constant of integration
so my overall answer is 4u^3/3-5ln|u|+c ?
yep
let me see if the program that my online hw uses accepts it
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ok cool it looks like it took it! heres the next one...
Evaluate the Integral of \[17\sqrt[3]{x}dx\]
Thank you for the help with the last one btw!
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