Question

I need help on the last part of my equation. The examples didn't show me how to do this part very well. How do I solve for k?
1.3 x 10^-2 M/min = k[0.15 M]^1[0.12 M]^2

Answer 1

K=0.01084.... I think or 1.1e-2

Answer 2

Can you show me how to do it? I'm taking the class online and the lessons are really bad.

Answer 3

The 1.3 * 10^-2 just wants you to move the decimal over two spaces (left for negative, right for positive) to make the number 0.013

Answer 4

Then 0.013= k ( mystery number) multiplied by the rest.

Answer 5

But I posted for help too... So don't take my word for it

Answer 6

LOL I was confused on what to do with the brackets

Answer 7

I'm making a B in chemistry right now, and feel like I'm trying to perform brain surgery every night

Answer 8

My teacher put in extra credit so I barely got an A and the lessons skip five steps at a time, it's getting harder and harder each time I try to do the homework

Answer 9

But thanks for helping :)

Answer 10

I feel your pain

Answer 11

hmmm you have to solve this algebraically

\(k=\dfrac{1.3 x 10^{-2}M/s}{[(0.15M)*(0.12M)^2]}\)

Answer 12

sorry the units on the rate (numerator) should be M/min