is the sqrt of 4 - (-5) undefined?
because you cant have a negative for a sqrt?
when you simplify 4 - (-5) what do you get?
√(4 - -5) √(4 + 5) √9 The square root of (4 - (-5)) is defined, because even though you can't take the sq.rt. of a negative number, the quantity isn't a negative number. 4 - (-5) is the same as saying 4 + 5, which just equals 9. You can take the square root of 9.
ohhhh 9
you can. at first i also thought it was sqrt(4 -5) = sqrt(-1). but it's not
ya silly
okay thnx =X
\(\large \sqrt{4-(-5)}\implies \sqrt{4-\times (-5)}\implies \sqrt{4-\times (-1\times 5)}\)
The square root is defined, because of the following below \[\sqrt{a+b} \neq \sqrt{a}+\sqrt{b}\] So you MUST evaluate whatever is under the square root before taking the square root.
hahah
shes gonna get confused look at all this math and proofs for why negative * negative = positive
im confused with this - Let h (x ) =sqrt 4 - x . Find h (0) +h (-5) because then it would be 9 and the sqrt of 9 is 3 and that is not one of my answers .........
is there an answer that says no
but "undefined " is so I was pushing the -1
h(0) = sqrt(4-0) = sqrt4 = 2 h(-5) = sqrt(4--5) = sqrt9 = 3 h(0) - h(-5) = 2 - 3 = -1
if it's plus. h(0) + h(-5) = 5
oh! got it i see now thanks!
I can understand why you were getting confused. So was I. But Dan815 gave the best answer
i totally didn't do the sqrt of 4
haha
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