Question

How is this simplified, really confused.
(x-1)^2-(x-1)

let f(x)=x^2-x and g(x)=x-1. Find (f o g)(x) and (g o f)(x)
so I got,
(f o g)(x)=f(g(x))=f(x-1)=(x-1)^2-(x-1),
the answer says its,
x^2-2x+1-x+1
so (f o g)(x)=x^2-3x+2

Answer 1

I cam up with this;
x^2-x+1-2x

Answer 2

you want to use the distributive property first
(x-1)^2-(x-1)

x^2-1-(x-1) For this step the 1 that isn't in parenthesis is actually 1^2 but 1^2 is 1 so I left it at that

Then you get rid of parenthesis
You will notice I make the (x-1) into x+1. This is because if you subtract a difference you end up adding the second term when you get rid of parenthesis

x^2-1-x+1

Combine like terms
Since -1+1 is 0, you can get rid of constants altogether.

x^2-x

The final answer is x^2-x although I should probably say "the simplified version of the expression (x-1)^2-(x-1) is x^2-x" because that is a lot more clear xD

Answer 3

So yea the answer is x^2-x

Answer 4

I have the answer in the book, it says x^2-2x+1-x+1=x^2-3x+2

Answer 5

really?

Answer 6

by the way please don't pay attention to mail from me malibug

Answer 7

why is there an equal sign in the answer? the question doesn't have one...

Answer 8

Ok I will put the whole question up because I think this confusing. I only the one part up because I was only stuck on that part.

Answer 9

oh what! yea always put up the whole thing

Answer 10

Sorry about that. I am confused how they got the simplified part?

Answer 11

\[(x-1)^2=(x-1)(x-1) \text{ \not } x^2-1\]

Answer 12

\[(x-1)^2=(x-1)(x-1)=x(x-1)-1(x-1)=x^2-x-x+1=x^2-2x+1\]


So you started out with:
\[(x-1)^2-(x-1)=(x^2-2x+1)-x+1\]
You can combine like terms from here

Answer 13

@malibugranprix2000, do you still need help with this?

Answer 14

@GABI.J I actually figured it out. Thanks.

Answer 15

Anytime, as long as you understand....

Answer 16

Thanks @myininaya really helped.