Question

Help me please? It's Algebra!
Put these in standard form:

One function, f(x), with two real rational solutions.
One function, g(x), with two real irrational solutions.
One function, h(x), with two complex solutions.
Create these three functions and explain how you know these functions meet each condition. Use complete sentences.
(Hint: Make sure that the b is even on g(x).)

Answer 1

What's the b?

Answer 2

I have no idea.

Answer 3

Is there a diagram or equation that goes with the question?

Answer 4

no

Answer 5

Okay. I know what the b is.

Think about the standard form of the equations we're discussing.

Ax^2 + Bx + C

I think that must be what they're referring to.

Answer 6

Note that they are asking about two solutions.

Answer 7

What does that tell you?

Answer 8

That they want two solutions?? lol

Answer 9

You seem to be in over your head. I can help, but we've got our work cut out for us.

Answer 10

Ax^2 + Bx + C is what a quadratic looks like.

Answer 11

Oh okay

Answer 12

How about I find a video that explains it? I think you need to review it.

Answer 13

I've already watched videos. I just don't get it.

Answer 14

Well, let's watch 'em together and talk about 'em. You'll save yourself a lot of aggravation in the future if you get a handle on what they're talking about now. Learn it once, and you don't have to go through this--except for a bit of refreshing from time to time.

Answer 15

I don't have that much time. I have to get this assignment in by 9 & there's still 3 more parts to it :/

Answer 16

Here's a video to get us started.

http://www.youtube.com/watch?v=CJwOhKrxxcg

It's short.

Answer 17

That's gives me 30 minutes

Answer 18

Do you think that we could get all of this done in 30 minutes?
1) Put these in standard form:

One function, f(x), with two real rational solutions.
One function, g(x), with two real irrational solutions.
One function, h(x), with two complex solutions.
Create these three functions and explain how you know these functions meet each condition. Use complete sentences.
(Hint: Make sure that the b is even on g(x).)

2) Explain how to convert f(x) into the general, vertex form of the equation. Use complete sentences. You may use the f(x) you created in question 1 as an example.

3) Find the solutions of g(x). Show each step.

4) Justify if completing the square is a good method for solving when the Discriminant is negative. Use any of your three functions as an example and respond in complete sentences.

Answer 19

You might want to think about that approach. When I was your age, that's the way I went about it. I wish I hadn't. For one thing I didn't learn or understand the stuff, and it was a huge pain learning it later in life. BELIEVE me when I say that. It really is easier when your *cough* *wheeze* younger. :

Answer 20

I think maybe I could do it for you. But that just leaves you in the predicament of having to go through this the next time you get the problem. ONLY It gets worse. If you don't know this stuff, it'll dog you all through the rest of your math classes.

Anyway, I'll do what I can.

Answer 21

Thank you. And I promise I'll watch all the videos & learn it myself afterwards. I just really need this finished.

Answer 22

Okay. But we need to watch that minute and a half long video in order to do this. I'll refer to it when I "help" you.

Answer 23

Okay!

Answer 24

So, the first two are not quadratic equations. They don't have two answers.

Answer 25

On the video, I mean.

Answer 26

I just watched the video. And okay.

Answer 27

Okay the third one is the one we're interested in. Notice where it is on the x-axis, that horizontal line.

Answer 28

It only touches the x-axis at one place, at zero, in this case.

Answer 29

What do you think that means? It's okay if you're not sure. But guess if you have to.

Answer 30

You there?

Answer 31

Strums fingers. Waits patiently.

Answer 32

Sorry, I had to feed my brother

Answer 33

Um.... Yeah I have no clue what that means @DonaldRoyMiller you there?

Answer 34

they are asking you to make several functions with a behavior as described.

for example if i'd say 2x^2+6x-2=0 would it fall under any of those categories and if so which one? and if not, why not?

Answer 35

Using \[\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\] you can find solutions for x. Because of the sign you get 2 solutions as long as the number under the root is greater than 0 thus. \[b^2-4ac>0\] means you will get 2 real solutions. \[b^2-4ac<0\] will give you 2 complex solutions
and if it's exactly 0 than you will only get 1 real solution.

The rational ones are even easier to find (and to create as well) simply by using brackets (x+p)(x+q) if you take any integer for p and q and if you solve the brackets you'll get a rational equation and you already know it's solutions (x=-p or x=-q).