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Find the equation of the tangent line to the curve y = 3tan x at the point (pi/4 , 3). The equation of this tangent line can be written in the form y = mx+b where m = b =
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First we want to find the derivative of y = 3tanx. You know how to do that?
dy/dx=2sec
No. If y = 3tanx Then y' = 3 sec^2(x)
The first derivative gives us the slope. So use it to find the slope our tangent line will need to have at the point (pi/4, 3)
yes
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I need m (the slope and b(yaxis)?
yes. first find m..the slope. then plug in m and (pi/4, 3) into y=mx + b and solve for b.
m=3
b=3
y=3(pi/4)+3
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3=3(pi/4)+B
need more help please
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