Question

A mixture contained CaCO3 and MgCo3. A sample of this mixture weighing 7.85g was reacted with excess HCl. The reactions are--
CaCO3 + 2HCl --> CaCl2 + H2O + CO2

MgCO3 + 2HCl --> MgCl2 + H2O + CO2

Is the sample reacted completely and produced 1.94L of CO2, at 25 degrees C, 785mmhg, whre were the percentages of CaCO3 and MgCO3 in the mixture?

Answer 1

what*
the*

Answer 2

it is essentially a mathematical problem ...

let x be the mass of the CaCO3 and Y be the mass of the MgCl2

when the CaCO3 reacts x/ 100 moles take part and x/ 100 moles of CO2 are formed

also when the MgCO3 reacts y/ 95 moles of CO2 are formed

we know that the total moles of CO2 = .0817 = x/100 + y/95

also in the original weight of salts x + y = 7.85

solving these 2 equations simultaneously I get y=6.08g and x =1.77g

mass of CaCO3 = 1.77g

Mass of MgCO3 = 6.08g

Answer 3

i see you know how to use google ;p

Answer 4

;D <3 lmfao I just thought you needed help and since I didnt have the answer I asked google ^_^ sorry

Answer 5

its okay thanks for trying!:)