A bicycle has tires of radius 0.35 meters. If the bicycle is traveling at a constant speed of 7.8 m/s, at approximately what angular speed are the tires rotating?
Circumference of tire?
2Pi r , right?
yah.
first I use formual V= r omega to find omega. then I conver rad/s to rev/ min. But i did not get right answer :(
\[ \left( \frac{7.8m}{s} \right) \left( \frac{2 \pi rad}{2 \pi r}\right) = \frac{7.8}{r}rad/s\] Why did you convert to rev/min?
that sounds like you did it right
does the answer have to be in rev/min?
yes
I donet get why you use (2pi rad/ 2pi r)
That's basically the formula you used; I was just doing a conversion. 2 pi radians per circumference. It's the V = r omega
the answer is 214
I get 213...
if you do like that you will have omega = 22.2 rad/ s
\[ \frac{7.8m/s}{.35m} \cdot \frac{ 1 \ rev}{2 \pi rad} \cdot \frac{60 s}{1 \ min} = 213 \]
that is the way i did , but i did not get right answer. I still dont understand
ok I got it
still dunno why it's 1 off tho... :P
no i got it now
nice ^_^
thanks I have some more question.
go for it ^^
a bicycle travels 141 m along a circular track of radius 15 m what is the angular displacement in radians of the bicycle from its strating postion ?
and a grindstone, initially a rest is given a constant angular acceleration so that is makes 20 rev in the first 8s what is angualar acceleration? (ans : 3.93 rad/S^2)
What's your try for the bike? Your intuition has been spot on for everything so far :)
:) bc bicycle is harder to ride than the car haaaaa
if you dont know it, we can skip it
^_^ lol I know it, just thought you might have a go. Circular motion is all pretty much conversion questions. What do you get when you divide the distance traveled by the bike by the circumference of the track?
the radius right
?? nope. Try again.
omg i have not idea
|dw:1382852419241:dw| You get the number of revolutions the bike has completed
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