Question

What is the molarity of solution containing 5.035grams of FeCl3 in enough water to make 500ml of solution?

Answer 1

molarity=no.of moles/volume in litre
molartiy=(w/m)/v
=w/(m*v)
w=5.035gm; m=molecular wight of fecl3; v=500/1000
jst put the values nd u will get the answer

Answer 2

\[FeCl_3 = 55.845 + 3(35.45) = 162.20g/mol\]\[\frac{5.035gFeCl_3}{500mL}\times\frac{mol}{162.20g}\times\frac{1000mL}{L}=\]