Question

calculus 2,

can you please tell me how to move on I am stuck ?
https://www.dropbox.com/s/sx6ezrrc6eqwhgv/Screenshot%202013-10-27%2015.10.02.jpg

Answer 1

thats where the integration ends.... and sec x . tan x= -sec x

Answer 2

No it doesn't ends there I have to replace theta

Answer 3

then @= tan^-1 x

Answer 4

integral csc x dx = ln |csc x +cot x| +c
use this!

Answer 5

i mean - ln |....|

Answer 6

ooh sec

Answer 7

csc x +cot x = (1+sec x)/tan x
see if you could prove this....

Answer 8

I mean like I don't need to make any modifications ?

Answer 9

integral csc x dx = -ln | (1+sec x)/tan x | +c

Answer 10

I can find it with triangle right ?

Answer 11

aaah

Answer 12

uhm still

Answer 13

-ln | (1+sec x)/tan x | +c = - ln |1+sec x| - ln |tan x|

Answer 14

= - ln |1+ \sqrt (1+x^2) | - ln x

Answer 15

sec theta = \sqrt (1+x^2)
tan theta = x

Answer 16

with the triangle method right ??

Answer 17

with any method .... just get that

Answer 18

csc x +cot x = (1+sec x)/tan x
once you prove this, other things are just resubstitution

Answer 19

because we know
sec theta = \sqrt (1+x^2)
tan theta = x

Answer 20

whats this /sqrt

Answer 21

\sqrt *

Answer 22

\(\sqrt {...}\)

Answer 23

`\(\sqrt{...}\)`
will give you
\(\sqrt{...}\)
here

Answer 24

oh I see ! thanks !

Answer 25

got the final answer correctly ?
welcome ^_^