OpenStudy (faith123):

If 24.6 grams of lithium react with excess water, how many liters of hydrogen gas can be produced at 301 Kelvin and 1.01 atmospheres? Show all of the work used to solve this problem. 2 Li (s) + 2 H2O (l) yields 2 LiOH (aq) + H2 (g

4 years ago
OpenStudy (zpupster):

Molecular weight of Lithium = 6.941 g/mol. From the reaction you have 2 moles of Li for every mol of H2 --2:1 (24.6 g of Li)(1 mol of Li/6.941 g of Li) = 3.544 moles of Li involved (3.544 moles Li)(1 moles H2/2 moles Li) = 1.772 moles of H2 Ideal Gas Law equation PV = nRT Therefore to find the Volume : n = 1.772 moles P = 1.01 atm T = 301 K R = 0.08205746 (L atm)/(mol K). This is to keep units consistency. Rearranging for Volume of H2 V = nRT/P --plug the values in and?=Liters

4 years ago
OpenStudy (faith123):

where do i plug them in at?

4 years ago
OpenStudy (faith123):

@zpupster

4 years ago
OpenStudy (zpupster):

to the eqution i gave you V = nRT/P

4 years ago
OpenStudy (faith123):

so i take all of the numbers you gave me and plug them in and thats the answer @zpupster

4 years ago
OpenStudy (zpupster):

yes

4 years ago
OpenStudy (faith123):

ok thankyou @zpupster

4 years ago
OpenStudy (zpupster):

good job!!

4 years ago
OpenStudy (faith123):

what units go behind it would it be latm/molK? @zpupster

4 years ago
OpenStudy (zpupster):

: n = 1.772 moles P = 1.01 atm T = 301 K R = 0.08205746 (L atm)/(mol K). This is to keep units consistency. you will end up with liters after cancelling i have to go now take care!!

4 years ago
OpenStudy (anonymous):

V = nRT / P V = ( (1.772 mol) * ( 0.0821 L atm/mol K) * 301 K ) / 1.01 atm V = 43.3 Liters

1 year ago
Similar Questions: