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Mathematics 7 Online
OpenStudy (anonymous):

I have a question about the area of the triangle. I need you to show me how to do this in the fastest way. Guide me, don't do my work!

OpenStudy (anonymous):

|dw:1382979424774:dw|

OpenStudy (anonymous):

AE+ED=AD=4, and ECD and EAB are similar (right?), so AE is to AB as ED is to CD. Can you take it from there?

OpenStudy (anonymous):

Well, the question doesn't say that ECD and AEb are proportional, so can we just assume that?

OpenStudy (anonymous):

See, they are right-angled, and share an angle at E (so all corresponding pairs of angles are equal, so triangles are similar).

OpenStudy (anonymous):

I thin I get that|dw:1382979848691:dw| so your saying if 2 angles are equal than the third triangles are also equal. Ok, then what?

OpenStudy (anonymous):

I mean 3rd angles, not 3rd triangles.

OpenStudy (anonymous):

Hmmmm, give me a minute or two.

OpenStudy (anonymous):

So AEB is times 3= AEC

OpenStudy (anonymous):

Not exactly but you are close.

OpenStudy (anonymous):

|dw:1382980036093:dw|

OpenStudy (anonymous):

Yes perfect!!!!! Now we need to find AE, Do you know how to do this?

OpenStudy (anonymous):

1 1/3?

OpenStudy (anonymous):

No wrong! hold on!

OpenStudy (anonymous):

Good! You caught yourself.

OpenStudy (anonymous):

|dw:1382980277212:dw|

OpenStudy (anonymous):

I will jump in when you need me i am going to be drawing it out so it will take a few minutes.

OpenStudy (anonymous):

So the triangles ECD and ABE are proportional b/c angles CED=AEB, angles BAE=EDC and therefore ECD=ABE.

OpenStudy (anonymous):

BAM! You got it!

OpenStudy (anonymous):

And AE= 3 /3 (b/c the triangles are proportional times 3) =1

OpenStudy (anonymous):

So ED=3

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