I have a question about the area of the triangle. I need you to show me how to do this in the fastest way. Guide me, don't do my work!
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AE+ED=AD=4, and ECD and EAB are similar (right?), so AE is to AB as ED is to CD. Can you take it from there?
Well, the question doesn't say that ECD and AEb are proportional, so can we just assume that?
See, they are right-angled, and share an angle at E (so all corresponding pairs of angles are equal, so triangles are similar).
I thin I get that|dw:1382979848691:dw| so your saying if 2 angles are equal than the third triangles are also equal. Ok, then what?
I mean 3rd angles, not 3rd triangles.
Hmmmm, give me a minute or two.
So AEB is times 3= AEC
Not exactly but you are close.
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Yes perfect!!!!! Now we need to find AE, Do you know how to do this?
1 1/3?
No wrong! hold on!
Good! You caught yourself.
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I will jump in when you need me i am going to be drawing it out so it will take a few minutes.
So the triangles ECD and ABE are proportional b/c angles CED=AEB, angles BAE=EDC and therefore ECD=ABE.
BAM! You got it!
And AE= 3 /3 (b/c the triangles are proportional times 3) =1
So ED=3
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