Question

calculus 2,

can you please help me with the first one ? Just so that I understand the logic

https://www.dropbox.com/s/a0pvl5ljyj4grrm/Screenshot%202013-10-27%2019.07.04.jpg

Answer 1

This might help you http://www.mathsrevision.net/advanced-level-maths-revision/pure-maths/algebra/partial-fractions

Answer 2

=A/(x-3) + B/(x+4)

Answer 3

take LCM

Answer 4

find A,B

Answer 5

and what is that ? what are the rules ?

Answer 6

whats LCM :D:D

Answer 7

Least Common Multiple - LCM

Answer 8

I might not know it cause you tel me with english term

Answer 9

what does this do ?

Answer 10

I suggest you try to understand the first answer i gave you.

Answer 11

\[ \frac{3x-1}{\color{red}{(x-3)} \color{blue}{(x+4)}} = {\frac{A}{ \color{red}{ x-3}}}+{\frac{B}{\color{blue}{x+4}}} \ \ \textrm{(this is all your problem is looking for)}
\\ \
\\ \
\\ \ = \frac{A \color{blue}{(x+4)} + B \color{red}{(x-3)}}{\color{red}{(x-3)} \color{blue}{(x+4)}} \ \textrm{(You use this to solve for A and B)}
\\ \
\\ \
\\ \ 3x-1 = A \color{blue}{(x+4)} + B \color{red}{(x-3)}
\\ \]

Answer 12

@AllTehMaffs, just curious: how do you change colors within your mathematical expressions?

Answer 13

"\fabulous"

;)

When you're setting up an expression
\[ \textrm{ \[ \frac{A + C}{ (4x+3) (6x-9)} \]} \]
\[ \frac{A + C}{ (4x+3) (6x-9)} \]

use \color{ * value} ie \color{red}

\[ \textrm{ \[ \frac{ \color{red} A + C}{ \color{red}{(4x+3)} (6x-9)} \]} \]
\[ \frac{ \color{red} A + C}{ \color{red}{(4x+3)} (6x-9)} \frac{\textrm{it either changes the single symbol directly next to it}}{ \textrm{or changes whatever you put in "{}"} }\]

Answer 14

nice work @AllTehMaffs

Answer 15

christos, tell us if you could not understand or have any doubt...