can someone help me with this. i dont get it.
step 1. Choose one of the groups of equations from the table below. Indicate which group you choose in your word processing file. Group 1 y = negative three-halvesx + 4 –3x + 2y = 8 Group 2 y = negative 2 over 3x – 2 –2x + 3y = -6 Group 3 y = negative 1 over 3x + 3 –x + 3y = 9 Group 4 y = negative 1 over 6x + 5 –x + 6y = 30 step 2. Type the first equation from the group you selected and identify the slope and the y-intercept of the equation. step 3. Describe how you would graph this line using the slope-intercept method. Be sure to write in complete sentences. step 4. Type the second equation from the group you selected and change the equation into slope-intercept form. Be sure to show all of your work. Identify the slope and y-intercept of the equation. step 5.Describe how you would graph this line using the slope-intercept method. Be sure to write in complete sentences. step 6. In a paragraph of at least three sentences, explain how the graphs of the two equations in your group are the same and how they are different. Be sure to use complete sentences.
any ideas
Well, choose a group first I guess.
i want to do group
4
huh?
technical dificulties, 1 sec 1D
lets start like this what is the slope and y intercept
Okay, fixed. So we have \[ y = - \frac{1}{6x + 5 - x - 6y} = 30 \] like that?
when you put an equation in slope intercept form, it looks like y = mx + b b is the slope intercept, and m is the slope
~b is the y-intercept
no like this \[y=-1/6x+5-x+6y=30\]
\[ \frac{1}{6x} or \frac{1}{6}x?\]
the second on but it has a negative sign in front of it
righto. cool beans. so let's get the y on one side, and all the x's on the other side \[ 6y = 30 - 5 + x + x/6\] follow?
nope explanation?
so our original equation is \[ -x/6 + 5 - x + 6y = 30\] does moving the -x to the right hand side make sense? \[ -x/6 + 5 + 6y = 30 + x\]
i have no idea how to do this im so done with math
:) no worries. We'll just do it 1 step at a time ^_^ So here's Group 4 \[ -x/6 + 5 - x + 6y = 30\] no matter what happens, we want to make sure to keep things equal. So whatever we do to one side of the equation, we have to do to the other. so to "move" -x from the left hand side to the right hand side, you add +x to each side of the equation, so that we know everything is equal \[( -x/6 + 5 - x + 6y) +x = (30) + x \] The +x and -x cancel out on the left hand side \[ -x/6 + 5 + \cancel{(x - x)}^0 + 6y = 30 + x \] leaving us with \[ -x/6 + 5 + 6y = 30 + x\]
okay i gottcha
Nice. So then we want to do that to -x/6 and +5 so that we can get y alone on the left hand side, and everything else on the right. \[ 6y = 30 + x + x/6 -5\] Can you simplify the right hand side?
how exactly
Grouping together the like terms makes it look like this \[ 6y = (30 - 5) + (x + x/6) \] and remember that when you add fractions, the bottom of the fraction has to be the same, and any number divided by itself is 1 \[ 1 + \frac{1}{6} = \frac{6}{6} + \frac{1}{6} = \frac{6+1}{6}\]
So what would the right hand side be?
6y=25+
i dont really like fractions so i wouldnt know how do finish the problem
Well fractions love you. And it's just like it would be with plain numbers. \[ x + \frac{x}{6} = \frac{6x}{6} + \frac{x}{6} = \frac{6x + x}{6} \] What's that equal?
umm im lost
im so done i jut cant
You can if you try, it's just something your brain hasn't done enough times to make it easy. The more you do it, the easier it gets! \[1 + \frac{1}{6} = \frac{6}{6} + \frac{1}{6} = \frac{6+1}{6} \]
its okay ill just get one of my teachers to help its fine i have other homework to do and also have lots of chores. sorry for wasting your time but thanks
You didn't waste my time at all :) I'll be glad to keep going if you want ^_^ Good luck with your other homework, and sorry I couldn't help more :(
its okay thanks though i wrote everything down so i have something to work with
Good luck!! ^_^
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