Question

Integration help in following questions

Answer 1

\[\Large \int\limits \frac{e^{\tan^{-1}x}}{(1+x^2)^2}dx\]
If i let arctanx=t then one power of (1+x^2) cancels out but 1 remains..what about it?

Answer 2

@hartnn

Answer 3

e^u/sec^2x
e^u cos^2x
int by parts

Answer 4

i mean e^t/sec^2t

Answer 5

as x = tan t

Answer 6

okay thanks!
\[\large \int\limits \frac{\sin2x}{a^2 \sin^2x+b^2 \cos^2x}dx\]

Answer 7

ye hai tere paas ?
Tutorial on Integration!
http://openstudy.com/users/hartnn#/updates/50960518e4b0d0275a3ccfba

Answer 8

arre hint dedo :/ isme shayad cos^2x se divide karte hain?

Answer 9

3rd point in tips

Answer 10

yes, divide N and D by cos^2 and then put t= tan x

Answer 11

okay!
\[\Large \int\limits \frac{\cos(x+a)}{\sin(x+b)}dx\]

Answer 12

kisse multiply divide karenge?

Answer 13

sochna padega,,,
wolf kya bolta hai ?

Answer 14

pata nahi..
aur first ques me integration cos^2t . e^t do baar parts lagega?

Answer 15

yes
cos (x+b) = cos [(x+a) - (b+a) ]
expand this and split the numerator

Answer 16

\[\Large \cos^2 t \int\limits e^t dt-\int\limits(-2\cos t \sin t \int\limits e^t dt)\]

Answer 17

fir usko sin2t likhdu? firse parts?

Answer 18

seems right...

Answer 19

yeah samja ?
cos (x+b) = cos [(x+a) - (b+a) ]

Answer 20

yeah wo agaya :)

Answer 21

aur fir cos2t aega usme teesri baar parts lagadu ? :/

Answer 22

aur wo cos(x+a) tha

Answer 23

yaar, wo mai nai kar rha.....mere paas paper pen nai hai, light bhi band ho gayi....kuch dikh nai raha...

Answer 24

okay :}

Answer 25

tan^-1 x ko t lete to pura kat jata ek term

Answer 26

tan^-1 x ko t hi to liya tha

Answer 27

tanx ko lia tha aapne

Answer 28

acha ha wahi sorry :P

Answer 29

par nahi ho raha :/

Answer 30

yaar, i can't do int by parts mentally...

Answer 31

by parts se nahi hoga ..bata raha hoon :/

Answer 32

http://www.wolframalpha.com/input/?i=integral+e%5Ex+cos%5E2x

Answer 33

arre fir sin2x cos2x ayi ja raha 3-4 baar by parts lagana padega :/

Answer 34

3 baar me hojaega..

Answer 35

itna bada problems dete hi kyu hai ye log :\

Answer 36

shayad koi aur chota logic ho..par abhi sochne ka time nahi..
\[\Large \int\limits \frac{\sqrt{\tan x}}{\sin2x}dx\]
koi idea?

Answer 37

answer mast hai iska :O

Answer 38

:o

Answer 39

http://www.wolframalpha.com/input/?i=integral+sqrt+%28tan+x%29%2Fsin+2x

Answer 40

ye ques maine kiya hua hai :/ kuch kuch yaad aa raha hai

Answer 41

kisi ko t subs karenge..par kisse

Answer 42

tanx?

Answer 43

=sec^2 x / sqrt tan x
then u = tan x

Answer 44

sqrt tan x /sin 2x = sec^2 x / sqrt tan x

Answer 45

kya kardia

Answer 46

okay!

Answer 47

sqrt tan x /sin 2x = (1/2)sec^2 x / sqrt tan x

Answer 48

sin 2x = 2 sin x cos x
= 2/ csc x swc x
...

Answer 49

samja?

Answer 50

sec^2x kaise aya?

Answer 51

sqrt tan x /sin 2x
= sqrt tan x csc x sec x
= tan x csc x sec x / sqrt tan x
= sec^2 / sqrt tan

Answer 52

tan csc = sin/cos * 1/sin = 1/cos

Answer 53

okay! hojaega ab :D
Last :D rest ill handle
\[\Large \int\limits e^x (\frac{(1-x)^2}{(1+x^2)^2}dx\]

Answer 54

form me nahi aa raha

Answer 55

ye easy lag rha hai...wolf me dallke answer bata zara..

Answer 56

e^x/1+x^2

Answer 57

ye pata hai
integral e^x (f(x)+f'(x)) dx
ruk ...

Answer 58

ha pata hai,form me nahi aa raha bus

Answer 59

list mein 26th dekh!

Answer 60

ohh...

Answer 61

(1-x)^2 = (x^2) - (2x)
split the numerator

Answer 62

-2x ?* okay!

Answer 63

1+x^2-2x

Answer 64

theek hai sojao ab :P thanks! <3

Answer 65

ab toh keys bhi nai dikh rahe keyboard ke...

Answer 66

:P

Answer 67

welcome ^_^