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Rank these in order from most acidic to most basic.
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How do I figure out their acidity or alkalinity?
\(\Large pH=-log[H^+]\) The lower the pH, the higher the acidity
First find out the pH of all 4. then you can order them
For 0.0018M KOH you need to figure out the pOH and then convert that to pH (see the conversion diagram I posted). for pOH=8.55 you convert that to pH 0.0023M HCl, just use pH=-log[H+] H+ is just 0.0023M since there is only 1 H in the compound. Same for KOH, the OH- concentration is 0.0018M because there is only 1 OH. Last one, the pH is already given. Then order them from low pH (acidic) to high pH (basic)
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