Question

I need help factoring:
2x^2+13x+15

Answer 1

x(2x+13) + 15

Answer 2

(x+5)(2x+3)

Answer 3

so then, what would be the zeros?
The orginal question was to find all the zeros of:
2x^3-3x^2-50x+75

Answer 4

Multiply the first coefficient 2 and the last term 15 to get 2*15 = 30

Then you need to find two numbers that multiply to 30 and add to 13 (the middle coefficient)

These two numbers are 10 and 3 since 10*3 = 30 and 10+3 = 13

Answer 5

so that means we break up 13x into 10x+3x and factor by grouping

Answer 6

-5, -3/2

Answer 7

2x^2+13x+15

2x^2+10x+3x+15

(2x^2+10x)+(3x+15)

2x(x+5)+(3x+15)

2x(x+5)+3(x+5)

(2x+3)(x+5)

Answer 8

I figured it out, Thanks!!!

Answer 9

If you want to factor 2x^3-3x^2-50x+75, then...


2x^3-3x^2-50x+75

(2x^3-3x^2)+(-50x+75)

x^2(2x-3)+(-50x+75)

x^2(2x-3)-25(2x-3)

(x^2-25)(2x-3)

(x-5)(x+5)(2x-3) ... use the difference of squares factoring rule



So that shows us that 2x^3-3x^2-50x+75 factors to (x-5)(x+5)(2x-3)

Answer 10

Ok I'm glad you figured it all out