Question

Logarithm NO DECIMALS

ln 12x^2 - ln3x

Answer 1

You can make use of the following ientities to solve the problem:
\[\ln(AB) = \ln(A) + \ln(B)\]\[\ln(A/B) = \ln(A) - \ln(B)\]\[\ln(x ^{n}) = nln(x)\]

Answer 2

*identities*

Answer 3

\[\Large \ln(12x ^{2}) -\ln(3x) = \ln(\frac{ 12x^{2} }{ 3x }) = \ln(4x)\]

Answer 4

so is that the final?

Answer 5

If you want you can write ln(4x) as ln(4) + ln(x).
But it is up to you. Either one should be okay.

Answer 6

can you do another one for me

Answer 7

sure.

Answer 8

e^x-1 - 3 =2

Answer 9

Is the exponent just x or (x-1)?

Answer 10

\[e ^{x-1} -3 =2\]

Answer 11

OK. Isolate the x term on the left. So add 3 to both sides:
e^(x-1) = 5
Take natural logarithm on both sides.
On the left ln and e will cancel out leaving just (x-1)
(x-1) = ln5
add 1 to both sides:
x = 1 + ln5

Answer 12

is that the final

Answer 13

yes.