HELP ME PLEASE 2^3x-1 = 4^x
Do you want to work from the same textbook?
\[2^{3x-1}= 4^{x}\]
Just curious because I'm not positive, but doesn't 4^x need to get changed to 2(2^x)?
close DonaldRoyMiller, but not quite
since 4 = 2^2 we can say this.... \[\large 2^{3x-1}= 4^{x}\] \[\large 2^{3x-1}= (2^2)^{x}\] \[\large 2^{3x-1}= 2^{2x}\]
They need a common base number, right. OH< HERE WE GO AGAIN WITH SOMEONE JUST GIVING AN ANSWER !!!!!!!!!!!!!!!!!
nope, I didn't give the answer since I didn't finish (you need to solve for x)
so please don't jump to conclusions and actually read what I posted
i SEE. Okay. You're right. But it's frustrating at how often that happens.
how do i solve for x??
What you do is ignore the base for now and focus on the exponent.
You aren't going to download the free textbooks are you.
solve 3x-1 = 2x
do i add the 1 to the 2?
You need to know the process, or you're going to have this same problem over and over again. Once you know how it works, you're good to go.
3x and 2x are two numbers being multiplied. So you have to work with likes. The one and the two are constants. They don't change. Know what I mean?
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