Please help its a chem question An infrared wave is measured to have a wavelength of 5.6 x 10^4 nm. What is its frequency?
for electrromagnetic radiation (in a vacuum) \[ c = f\lambda \\ \ \\ c = \ \textrm{speed of light} = 3.0 x 10^8 m/s \\ f = \ \textrm{frequency in Hertz (1/s)} \\ \lambda = \ \textrm{wavelength (in meters)} \]
@AllTehMaffs alright it would be f = frequency I need help solving it
\[ f = \frac{c}{\lambda} \] what's your wavelength in meters?
5.4 x10^12
@AllTehMaffs
... no. should be very small
I'm not sure than @AllTehMaffs
5.6x10^4 nm 56000nm ( 1x 10^-9)m/nm = 5.6x10^-5 m
oo ok thank you could you help me with one more? @AllTehMaffs
sure ^^ Did you finish that one? c / that number?
Almost all commercially available microwave ovens employ radiation with a frequency of 2.45 x 109 Hz. Calculate the wavelength of this radiation.
@AllTehMaffs yes I got 1.7857143e-13
that's really, really small. It should be pretty large. did you divide that number by c instead? it should be about 10^12
or it should be 10^13
not -13
yes I did c and thats what I got
@AllTehMaffs
(3 x 10^8 / 5.6 x 10^-5) = 5.36 x 10^12 1/s I'm so sorry, that's what you got originally. I couldn't tell what thing you were talking about without units
its fine haha @AllTehMaffs
^^ what's your next question?
Almost all commercially available microwave ovens employ radiation with a frequency of 2.45 x 109 Hz. Calculate the wavelength of this radiation. @AllTehMaffs
same deal as last time, this time it's c/f
ok than you I understand now
welcome ^^ .122m yah?
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