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Mathematics 22 Online
OpenStudy (anonymous):

PLEASE HELP. solve the system by elimination?

OpenStudy (anonymous):

Hint : start with the first two and multiply the second one by -1 to eliminate x.

OpenStudy (anonymous):

what

OpenStudy (anonymous):

Ed is suggesting you multiply the second equation by -1 and then add the first two equations together. The x terms will sum to zero. You can also sum the first and last equations eliminating x. That would leave you two equations with two variables. Is that making sense?

OpenStudy (anonymous):

THIS IS SO HARD YOU GUYS

OpenStudy (anonymous):

No worries, let's take it one step at a time okay? I'll help you.

OpenStudy (anonymous):

Take the first expression and add it to the second expression (after multiplying each term in the second expression by -1 to change their sign) -2x +2y + 3z = 0 +( 2x + y - z= 3) ______________________ what do you get?

OpenStudy (anonymous):

do u still need help? @veganbee

OpenStudy (anonymous):

@helpme1.2 yeah lol.

OpenStudy (anonymous):

After you add the two expressions above you get 3y + 2z = 3. Does that make sense? Note the x terms add to zero.

OpenStudy (anonymous):

We can do the same adding the first and last expressions -2x +2y + 3z = 0 + 2x +3y + 3z = 5 ____________________ 5y + 6z = 5 Now we have two equations with two variables: 3y + 2z = 3 5y + 6z = 5 Can you solve two equations with two variables? You could use elimination or substitution.

OpenStudy (anonymous):

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