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Find the derivative of y=x^5lnx-1/4x^4
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@jim_thompson5910 :D?
\[\Large y\quad=\quad x^5 \ln x-\frac{1}{4}x^4\]\[\Large y'\quad=\quad \color{royalblue}{(x^5)'}\ln x+ x^5\color{royalblue}{(\ln x)'}-\frac{1}{4}\color{royalblue}{(x^4)'}\]For the first term, we'll need to apply the product rule, yes? The blue parts represent derivatives we need to take.
5x^4lnx+x^5*1/x-1/4(4x^3)
@zepdrix
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Ya looks good so far! Now it just needs a little simplification.
x^4+5x^5ln(x)-x^3?
\[\Large y'\quad=\quad x^4+5x^{\color{red}{5}}\ln(x)-x^3\]Hmm looks ok besides this one small part here.
5x^4lnx+x^4-x^3!
yay good job!
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