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SURFACE AREA OF A RIGHT CONE. ILL BUMP YOUR SCORE :D
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You supposed to use a formula, or calculus?
formula i guess ... but ive tryed so many and it doesnt work
so any way you know how works for me
I don't remember any formula for this. To derive it, I would use \[ \int_0^h 2\pi\left(\frac bh\right)x\; dx=\pi \frac bhx^2\Bigg|_0^h = \pi bh \]In this case \(b=8\) and \(h=\sqrt{14^2-8^2}\) by Pythagorean theorem.
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Hmmm, let me see
However for some reason that isn't right... Hmmmm
thats what im saying everything i try isnt right :(
@zepdrix help :(?
I'm getting 176
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ill try it thank you! can you show me how you did it ?
I tried \[ \pi(8)(14)+\pi 8^2 \]
Thank you
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