Question

2log base 4 8 = 3x

Answer 1

\[2\log_{4} 8 = 3x\]

Answer 2

Rewrite the left side as: log (8)^2 with base 4, and the right side remains the same.

Because the Law of Logs states that log(a^r) = r log (a).

Now write that log equation as an exponential equation:

4^(3x) = 8^2
Now you have an exponential equation, which you will change both bases, to base 2, as 4= 2^2 and 8 = 2^3.

So, 2^2(3x) = 2^6

6x = 6

x = 1_