Water's heat of fusion is 80. cal/g , and its specific heat is 1.0calg⋅∘C . Some velomobile seats have been designed to hold ice packs inside their cushions. If you started a ride with ice packs that held 1400g of frozen water at 0 ∘C , and the temperature of the water at the end of the ride was 32 ∘C , how many calories of heat energy were absorbed?

Question

Water's heat of fusion is 80. cal/g , and its specific heat is 1.0calg⋅∘C .  Some velomobile seats have been designed to hold ice packs inside their cushions. If you started a ride with ice packs that held 1400g of frozen water at 0 ∘C , and the temperature of the water at the end of the ride was 32 ∘C , how many calories of heat energy were absorbed?

joannablackwelder · Answer

I found the energy it took to raise the temperature of the ice from 0-32 deg C (using the specific heat of water as 1 cal/(g deg C) and then added the energy to melt the ice into liquid water using the heat of fusion. I am assuming that all the ice is melted.