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HELPP rationalize the denominator √4/√2
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is that \[\frac{\sqrt4}{\sqrt2}\] ? or \[\sqrt\frac{4}{\sqrt2}\]
first one
\[\frac{\sqrt4}{\sqrt2}=\frac{\sqrt4}{\sqrt2}\times1\\\qquad =\frac{\sqrt4}{\sqrt2}\times\frac{\sqrt 2}{\sqrt 2}\\\qquad=\]
is that the answer?? √2/√2
or √2/2
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not quite, , what do you get when you multiply the denominators ?
√2
im trying to find the X intercept when y=0 for y=-2(x+3)^2 + 4
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is there any reason it is not easier just to write \[\frac{\sqrt4}{\sqrt2}=\sqrt{\frac{4}{2}}=\sqrt2\]
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thank u :)
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