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Chemistry 10 Online
OpenStudy (anonymous):

What mass of O2 is required to produce 14.5 g of CO2 if the reaction has a 65.0 % yield? CH4 + O2 ® CO2 + H2O

OpenStudy (joannablackwelder):

I would use the percent yield and amount of CO2 formed to calculate the theoretical amount of CO2 possible. From this, I can convert to mass of O2 using molar masses and molar ratio.

OpenStudy (jfraser):

working backwards, i would start with the 14.5g of \(CO_2\) being 65% of the predicted yield, so I'd find the theoretical yield first, then find the mass of \(O_2\) that should produce that much \(CO_2\)

OpenStudy (jfraser):

\[65\% yield = \frac{14.5g}{theoretical}\] and solve for the theoretical mass first

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