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What mass of O2 is required to produce 14.5 g of CO2 if the reaction has a 65.0 % yield? CH4 + O2 ® CO2 + H2O
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I would use the percent yield and amount of CO2 formed to calculate the theoretical amount of CO2 possible. From this, I can convert to mass of O2 using molar masses and molar ratio.
working backwards, i would start with the 14.5g of \(CO_2\) being 65% of the predicted yield, so I'd find the theoretical yield first, then find the mass of \(O_2\) that should produce that much \(CO_2\)
\[65\% yield = \frac{14.5g}{theoretical}\] and solve for the theoretical mass first
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