Question

Write the equation in standard form of the line through the points (-1,-3) and (2,-1)

Answer 1

did you find the slope?

Answer 2

2/3?

Answer 3

@satellite73

Answer 4

yes, right 3, up 2 slope is \(\frac{2}{3}\)

Answer 5

now pick a point and write the point slope formula
\[y-y_1=m(x-x_1)\] if you pick \((2,-1)\) you get
\[y+1=\frac{2}{3}(x-2)\]

Answer 6

solve for \(y\) and you aer done

Answer 7

what is the final answer? @satellite73

Answer 8

i don't know, i didn't do it

Answer 9

I am not really sure how to solve it

Answer 10

\[y+1=\frac{2}{3}(x-2)\]steps are always the same,
distribute first, get
\[y+1=\frac{2}{3}x-\frac{4}{3}\]
then subtract \(1\) from both sides and get
\[y=\frac{2}{3}x-\frac{7}{3}\]

Answer 11

isn't that slope intercept form?

Answer 12

yes it is
what form do you want it in?

Answer 13

standard

Answer 14

ooh if i could read "Write the equation in standard form " i would know

Answer 15

its fine

Answer 16

in that case start with
\[y+1=\frac{2}{3}(x-2)\] then multiply both sides by \(3\) to get rid of annoying fraction and get
\[3y+3=2(x-2)\] first

Answer 17

then distribute to get
\[3y+3=2x-4\]

Answer 18

subtract \(3y\) and get
\[3=2x-3y+4\] then subtract \(4\) to get
\[-1=2x-3y\] or if you prefer
\[2x-3y=-1\]