can someone help me where I'm going wrong? :(
(1 pt)
A producer finds that demand for his commodity obeys a linear demand equation , p+11x=30 where P is in dollars and X in thousands of units. If the cost equation is c(x)=8.8x^2+20x+2.5 , what price should be charged to maximize the profit?
The price to maximize the profit is $ .
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OpenStudy (anonymous):
i found the price: p=(30-11x)*x
OpenStudy (anonymous):
30x-11x^2- (8.8x^2+20x+2.5)
OpenStudy (anonymous):
= 10x-19.8x^2-2.5
OpenStudy (anonymous):
the i find the derivative: dp/dx and set it to zero.... i got x= .252525
OpenStudy (anonymous):
then i tried to plug into c(x) but it's wrong :((
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OpenStudy (anonymous):
i got 8.05
OpenStudy (anonymous):
OpenStudy (mertsj):
Isn't profit= revenue - cost?
OpenStudy (anonymous):
yeah
OpenStudy (mertsj):
I got 6.87 for the price
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OpenStudy (anonymous):
how? it says its not correct..
OpenStudy (mertsj):
price = (30-11x)x
OpenStudy (anonymous):
right.
OpenStudy (mertsj):
So if x = .25, price = (30-11/4).25=6.68
OpenStudy (mertsj):
All depends on how many significant digits you carry for x
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OpenStudy (anonymous):
i tried that one too
OpenStudy (anonymous):
its wrong.
OpenStudy (mertsj):
cost per unit is c(x)/x
OpenStudy (anonymous):
ok
OpenStudy (mertsj):
If you want price per unit shouldn't you divide the price by 1000 since x is 1000 units?
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OpenStudy (anonymous):
howd you get that
OpenStudy (mertsj):
and X in thousands of units.
I read the problem you posted.
OpenStudy (anonymous):
yeah can you tell me where i went wrong?
OpenStudy (mertsj):
Well, I am not sure but I would try dividing the answers we got by 1000 and see if that is the price per unit.
OpenStudy (anonymous):
whered you get 1000 from?
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OpenStudy (mertsj):
What does x represent?
OpenStudy (anonymous):
the price
OpenStudy (mertsj):
Read the problem. What does x represent.
OpenStudy (anonymous):
thousands in units.
OpenStudy (mertsj):
So when you got x = .25 that meant .25 thousands of units of 250 units.
So when you got 6.87 for the price of x units that was for 1000 units. So each unit should be sold for 7 cents
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OpenStudy (anonymous):
okay... so i got x= .25 and i times that by 1000...
OpenStudy (anonymous):
so whats the correct answer?
OpenStudy (anonymous):
im getting it wrong.
OpenStudy (mertsj):
So if x = .25, price = (30-11/4).25=6.68 for 250 units.
6.68/250=668 cents/250= 3 cents per unit. Try that. How many chances do you get?
OpenStudy (anonymous):
huh?
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OpenStudy (mertsj):
I think the part you can't get a handle on is that x is in thousands of units. So if x is 1 that is 1000 units. If x = 2, that is 2000 units. If x = .25 that is 250 units.
OpenStudy (anonymous):
right.
OpenStudy (anonymous):
i understand that part.
OpenStudy (mertsj):
What did you get for x?
OpenStudy (anonymous):
555003.
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OpenStudy (mertsj):
Well that is not what you posted earlier.
OpenStudy (anonymous):
i plugged in 250 into c(x)
OpenStudy (anonymous):
i dont know.
OpenStudy (anonymous):
whats the answer then?
OpenStudy (anonymous):
isn't it .252525 *1000 = x= 252.525
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OpenStudy (mertsj):
I don't know for sure. I wanted you to try 3 cents and I asked you how many chances you get at entering the correct answer and you didn't answer me.