Question

Find the derivative of the function.
h(x) = log6(x2 + x)

Answer 1

Seems like a true-blue application of the chain rule?

Answer 2

that, and the fact that
\[\log_6(x)=\frac{\ln(x)}{\ln(6)}\] so the derivative of
\[\log_6(x)\] is
\[\frac{1}{\ln(6)x}\]

Answer 3

anytime you're ready @arshia93 ^_^

Answer 4

i put \[\frac{ 1 }{ (2x+1)\ln6 }\] but that came out incorrect.

Answer 5

@terenzreignz

Answer 6

Chain rule though.
Bit by bit...

Answer 7

Remember...\[\Large \frac{d}{dx}f(g(x))= f'(g(x)) g'(x)\]

Answer 8

So you could take
\[\Large f(x) = \log_6(x)\]\[\Large g(x) = x^2 +x\]

Answer 9

im supposed to fin detivative of x^2+x correct?
So i included (2x+1) with the fraction from log6

Answer 10

is it not included in the fraction?

Answer 11

Let me be more blunt about it ^_^
\[\Large \frac{d}{dx} \log_6[g(x)]= \frac{g'(x)}{g(x)\ln (6)}\]

PLEASE review the chain rule.

Answer 12

\[\frac{ 2x+1 }{ \ln6(x^2+x) }?\]

Answer 13

when you use the chain rule never change the input!!

Answer 14

yes