Any good with Trignometry? Please help with this problem:
Heres the problem: \[(\sqrt[3]{x+1})^{3}-1\]
Where's the trig?
Its above.
Unless I'm missing something, the answer's "x".
haha, that is the answer. But I'm trying to figure out how to get to that answer.
How so?
Idk. I don't really understand how to solve it.
Well, you're just cubing the cubed root of "x+1", which gets you back to where you started (i.e. "x+1"). And then you subtract "1", leaving you with "x".
but ... you have an index. =\
Well ... the root.
Thats what killed me.
What's confusing you?
The root of 3.
Oh, yeah, that just means "cubed root". To make things easier, you can always convert that to exponents.
So, if you see: \[\sqrt[3]{x}\] You can rewrite it as: \[x ^{\frac{ 1 }{ 3 }}\] i.e. to "x" raised to the one-third power.
Ohhh. So lets work this out together.
\[\sqrt[3]{(3)^{3}-1}\]
cubed root of 26
Hahaa. WTH? How are you getting that!!!!! hahaa.
BREAK IT DOWN ... all the way for me man!
If you have a calculator handy you can write: \[(26)^{\frac{ 1 }{ 3 }}\]
How did you get 26 though.
NVM!
I just did it in my head. (3)^3-1 = 26
Ok so where are we right now? Meaning: what else is a little foggy for you?
Im going to solve this problem: \[(\sqrt[3]{x+1})^{3}-1\]
Im guessing the answer is just X ?
Yeah, it should be...
Sweet! Im starting to get the hang of this now.
Great! If you have any other questions just ask.
I dont understand how the root comes into the answer and sometimes it cancels out. For example: \[(\sqrt[3]{x+1})^3-1 = x\] BUT : \[(\sqrt[3]{(3)^3-1} = x\] = \[(\sqrt[3]{26}\]
Yeah--good question. It's because those two expressions on the lefthand side are NOT equal.
Think of it this way. Actually, just forget about roots for a second. Is \[(x+1)^{3}\] the same as: \[x^{3}+1\]
Sometimes, the two expressions MIGHT be equal but are they ALWAYS equal? No way!
oooooh. Sweet !
(x+1) ^3 isn't the same as x^3+1
No, \[(x+1)^{3} = x ^{3}+3x ^{2}+3x+1\]
That's called an IDENTITY because it is always true no matter what value you choose for "x".
And in trig you'll see a lot of Trig IDENTITIES
Oh okay. So that mean that when Im solving the root values, I have to watch out then. For some reason it feels like i need a little clarification on remembering when and when not to bring down the root.
The identities thing is understandable though.
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