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Calculus1 7 Online
OpenStudy (anonymous):

Suppose [g(x)]^2+12x=x^2*g(x) and g(4)=12. Find g'(4)?

hartnn (hartnn):

do you know chain rule ?

OpenStudy (anonymous):

I know what the chain rule is but I don't know how to apply it this one

hartnn (hartnn):

ok, d/dx [g (x)]^2 = 2 g(x) d/dx [g(x)] does this make sense ?

OpenStudy (anonymous):

It makes sense

hartnn (hartnn):

good, and can you differentiate x^2*g(x) using product rule ?

OpenStudy (anonymous):

2x*g(x)+g'(x)*x^2 right?

hartnn (hartnn):

correct! :)

hartnn (hartnn):

so, what do we have now ? 2 g(x) g'(x) +12 = 2x*g(x)+g'(x)*x^2 right ? with me till here ?

OpenStudy (anonymous):

Yeah, I got it

hartnn (hartnn):

now to get g'(4) , just plug in x=4 ! replace x by 4 wherever you see it there ..

hartnn (hartnn):

could you find g'(4) ?

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