Question

2nd implicit derivative of sinx+x^2*y=1?
The first one is -2xy+cosx/x^2

Answer 1

first one is :\(-2y-2xy'+\huge\frac{-x^2sinx -2x cosx}{x^4}\)

Answer 2

How did you get that?

Answer 3

by differentiating implicitly

Answer 4

I'm just confused because I got a different answer for the first derivative

Answer 5

\(d/dx( x^2y) +d/dx(cosx/x^2)\)

Answer 6

treat y like function of x, \(y(x)\). So it will have a derivative respect to x, \(y´\). Rest is just differentiation of composite functions

Answer 7

myko found 2nd differentiation

Answer 8

ups, sry. I think I made a mistake. :) i differentiated you answer and not the function. At least I started with your function and contiunued with the answer....

Answer 9

and isn't the 1st one
(-2xy-cosx)/x^2
??

Answer 10

and in your answer should be: -2xy^2+x^2y'+cosx=0

Answer 11

see if you get y' =(-2xy-cosx)/x^2

Answer 12

so u got this as y' ?