Dear All, Please share the formula to find the volume of metal sheet used in a Hollow cylinder ...
Volume V = π×h×(R² − r²) = π × h × (D² − d²) ⁄ 4 Surface to volume ratio SA:V = 2 × (R − r + h) ⁄ (h × (R − r)) Surface Area (SA), Outer Lateral lS = 2×π×R×h Surface Area (SA), Inner Lateral ls = 2×π×r×h Surface Area (SA), Total Lateral l = lS+ls = (2×π×R×h)+(2×π×r×h) = 2×π×h×(R+r) Surface Area (SA), Base B = π × (R² − r²) Surface Area (SA), Total A = 2 × B + l = (2 × π × (R² − r²)) + (2 × π × h × (R + r)) = 2 × π × (R² − r² + h × (R + r)) = 2 × π × (R+r) × (R − r+h) Outer diameter D = 2×R Inner diameter d = 2×r Outer radius R = D ⁄ 2 Inner radius r = d ⁄ 2 Base outer perimeter P = 2×π×R Base inner perimeter p = 2×π×r
thanks....
but........I want to information.......about volume of Metal used in a Hollow cylinder.......
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What you want is the volume of the metal sheet, essentially the ring. So take the difference between the volume of the external cylinder and the internal one
Cut the cylinder along its height. It becomes an open sheet. area = pi*d*h vol=pi*d*h*thickness. That is the amount of material is present. Note: 25.4mm=1.0" 10mm=1*10/25.4=0.3936"
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